5x^2+10x=16x-2x^2

Solution for 5x^2+10x=16x-2x^2 equation:

5x^2+10x=16x-2x^2

We move all terms to the left:

5x^2+10x-(16x-2x^2)=0

We get rid of parentheses

5x^2+2x^2-16x+10x=0

We add all the numbers together, and all the variables

7x^2-6x=0

a = 7; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·7·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*7}=\frac{0}{14}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*7}=\frac{12}{14}
=6/7
$